Marie Euphrosyne Spartali (1844 – 1927). British Pre-Raphaelite painter
of Greek descent, arguably the greatest female artist of that movement.
During a sixty-year career, she produced over one hundred and fifty
works, contributing regularly to exhibitions in Great Britain and the
United States.
She and her cousins
Maria Zambaco and Aglaia Coronio
were known collectively among friends as "the Three Graces", after the
Charites of Greek mythology (Aglaia, Euphrosyne and T
halia),
as all three were noted beauties of Greek heritage. It was in the house
of the Greek businessman A.C. Ionides (1810–1890) at Tulse Hill, in
south London, that Marie and her sister Christine (1846–1884) met
Whistler and Swinburne for the first time. They were dressed in white
with blue ribbon sashes. Swinburne was so overcome that he said of
Spartali: "She is so beautiful that I want to sit down and cry". Marie
was an imposing figure, around 1.9 metres (6 ft 3 in) tall and, in her
later years, dressed in long flowing black garments with a lace hood,
attracting much attention throughout her life.
She modelled for:
Brown; Burne-Jones (The Mill); Julia Margaret Cameron; Rossetti (A
Vision of Fiammetta, Dante's Dream, The Bower Meadow); and Spencer
Stanhope.
In 1871, against her parents' wishes, she married American
journalist and painter William J. Stillman. She was his second wife,
his first having committed suicide two years before. The couple had
posed for Rossetti in his famous Dante pictures, though it is not
certain if that is how they first met. She also travelled to America,
and was the only Britain-based Pre-Raphaelite artist to work in the
United States.
|
A Vision of Fiammetta, by D. G. Rossetti |
|
The
Lady Prays - Desire (self-portrait) |
|
Spartali by Rossetti |
|
Self-portrait |
|
Self-portrait On A Balcony |
The first painting shown is not Marie Stillman; it is a model named Alexa Wilding.
ReplyDeleteDo you mean the painting A Vision of Fiammetta? Apparently it is Stillman http://www.rossettiarchive.org/docs/s252.rap.html
DeleteBut I agree in this painting she looks very much like Alexa Wilding.